Why Matlab Function block don't perform operations in matrix of different size? (Matlab2019a)

1 回表示 (過去 30 日間)
Rubem Pacelli
Rubem Pacelli 2020 年 1 月 30 日
コメント済み: Rubem Pacelli 2020 年 1 月 31 日
In Workspace, if a you have a matrix A of size [8 5] and a matrix B of size [1 5], you could perform the following operation:
A-B
the row in B will be used for each line on A. But Matlab Function block doesn't able to perform this operation. You will recieve this error:
Size mismatch (size [8 x 5] ~= size [1 x 5])
What is the problem with handling this in the Matlab function block?

サインインしてこの質問に回答する。

採用された回答

Walter Roberson
Walter Roberson 2020 年 1 月 30 日
MATLAB Function Blocks are processed by something similar to MATLAB Coder, and do not support full MATLAB. In particular, implicit expansion is not supported at this time. Try bsxfun(@minus, A, B)

その他の回答 (0 件)

カテゴリ

Help Center および File Exchange で Simulink Functions についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by