ODE: How can I trace changing of all parts of equation during solving

1 回表示 (過去 30 日間)
Uladzislau
Uladzislau 2020 年 1 月 22 日
コメント済み: Uladzislau 2020 年 1 月 22 日
Hello! I'll be grateful if someone could help me. So the question is:
I have an ODE that is been solved correctly.
function [out] = chua(t,in,alpha, beta, A, C, u1st)
x = in(1);
y = in(2);
z = in(3);
xdot = -alpha*((3*A*u1st^2+C+1)*x-y) ...
-3*A*alpha*u1st*x^2...
-A*alpha*x^3;
ydot = x - y + z;
zdot = -beta*y;
out = [xdot ydot zdot]';
The call is:
t = [0 2400];
y = [0.004 0 0];
alpha = 15.6;
beta = 28;
A = 0.002;
C = -1.3;
u1st = 0.5;
[t,y] = ode45(@(t, y) chuaModIris(t, y, alpha, beta, A, C, u1st), t, y );
plot3(y(:,1),y(:,2),y(:,3))
But on each step of integration I need to get extra data - parts of the first equation:
SquarePart = -3*A*alpha*u1st*x^2;
and
CubicPart = -A*alpha*x^3;
Actually, I've already done it in Simulink, but I haven't any idea how to implement it in m-file.

採用された回答

darova
darova 2020 年 1 月 22 日
What about this?
[t,y] = ode45(@(t, y) chuaModIris(t, y, alpha, beta, A, C, u1st), t, y );
plot3(y(:,1),y(:,2),y(:,3))
SquarePart = -3*A*alpha*u1st*y(:,1).^2;
CubicPart = -A*alpha*y(:,1).^3;
  1 件のコメント
Uladzislau
Uladzislau 2020 年 1 月 22 日
So obvious, but I haven't seen such simple way! Thank you!!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeOrdinary Differential Equations についてさらに検索

タグ

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by