hello,
I have a matrix defined like this :
2 6 10 14 18 22 26
1 4 8 12 16 20 24
1 3 6 10 14 18 22
1 3 5 8 12 16 20
1 3 5 7 10 14 18
1 3 5 7 9 12 16
1 3 5 7 9 11 14
1 3 5 7 9 11 13
after I use rref() I get the reduced matrix and i see that i have all but one leading coulmns.
is there a function that gives me the basis of the column space from the original matrix?
"colspace" gives me something different than i need.
Thank you in advance!

2 件のコメント

David Goodmanson
David Goodmanson 2020 年 1 月 1 日
Hi shlomo,
what do you need for the column space to look like? Since the rank of m is 7, the columns of m itself form a column space, and so do do the columns of [m multiplied on the right by any nonsingular 7x7 matrix]. The possibilities cover a lot of territory.
shlomo shnur
shlomo shnur 2020 年 1 月 1 日
thank you for the quick answer,
basicly i want to output the basis with the same numbers of the original matrix.
thank you very much.

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