mean value of array
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I would appreciated if someone can tell me what am I doing wrong or maybe ?
all the matrix are 20x1 in my varibles
[Relative_ErrorM, indexAtM] = mean(Relative_Error,'omitnan');
r_experM= r_exper(indexAtM,);
plot(r_experM,Relative_ErrorM, 'kv', 'LineWidth', 2, 'MarkerSize', 15);
text(r_experM,Relative_ErrorM,sprintf(' Mean = %.1f', Relative_ErrorM))
here is the error message
Error using mean
Too many output arguments.
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その他の回答 (1 件)
Image Analyst
2019 年 12 月 15 日
0 投票
Note that the mean of an array won't necessarily fall at ANY index. It's quite possible the mean is not one of hte numbers in the array. For example mean([1,2]) is 1.5 but 1.5 is not in the array. Did you perhaps mean min() or max() instead of mean()? Those functions can return the index where the first occurrence of the min or max appears.
2 件のコメント
amjad almaarafawi
2019 年 12 月 15 日
Image Analyst
2019 年 12 月 16 日
No, since you don't have an "x" value. However, you can put a marker on the actual value that is closest to the mean.
plot(x, y, 'b-', 'LineWidth', 2); % Plot curve.
% Find mean y value.
meanYValue = mean(y);
% Find out differences between actual y values and the mean y value.
diffs = abs(y - meanYValue);
% Find the index the y value is closest to the mean y value.
[minDiff, indexAtMinDiff] = min(diffs);
% Plot a circle around that point.
hold on
plot(x(indexAtMinDiff), y(indexAtMinDiff), 'ro', 'MarkerSize', 20);
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