arrays within for loop
古いコメントを表示
for k=1:+1:4
S=(1/(k+1))*(m-b*y-m*r);
I=(1/(k+1))*(a*e-(m+r)*i);
y=y+(S*I);
end
I want to store values of S in ascending array and I in descending array then I'll get required y
can anyone help me with this code please.....
回答 (1 件)
KALYAN ACHARJYA
2019 年 12 月 1 日
編集済み: KALYAN ACHARJYA
2019 年 12 月 1 日
for k=1:4
S(k)=(1/(k+1))*(m-b*y-m*r); % How to get y here?
I(k)=(1/(k+1))*(a*e-(m+r)*i);
end
S=sort(S);
I=sort(I,'descend');
%Now Calculate Y
Or
y=zeros(1,4)
for k=1:4
S(k)=(1/(k+1))*(m-b*y(k)-m*r);
I(k)=(1/(k+1))*(a*e-(m+r)*i);
y(k+1)=y(k)+(S(k)*I(k));
end
S=sort(S);
I=sort(I,'descend');
% Canculate y again % I didnot find any sense here
カテゴリ
ヘルプ センター および File Exchange で Loops and Conditional Statements についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!