Help on understanding the following matlab code ?

xt= 15 10 5 0
11 6 1 4
7 2 3 8
3 2 7 12
1 6 11 16
[~,J]=min(flipud(xt),[ ],2)
----------------------------------------------------------
Output J= 1
2
2
3
4

 採用された回答

Jan
Jan 2019 年 11 月 22 日

0 投票

Step by step:
  • flipud(xt): This flipps the order of elements vertically. Try it:
x = rand(3,2)
flipud(x)
  • min(Y, [ ], 2) : find the minimal value along the 2nd dimension
  • [~, J] = ... : Ignore the first output and assing the 2nd output to the variable J
See also:
doc flipud
doc min

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeCreating and Concatenating Matrices についてさらに検索

質問済み:

2019 年 11 月 22 日

回答済み:

Jan
2019 年 11 月 22 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by