reading and splitting csv file

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Francesco Giuseppe Fornari
Francesco Giuseppe Fornari 2019 年 11 月 19 日
回答済み: Francesco Giuseppe Fornari 2019 年 11 月 22 日
Hi,
I'm having troubles with a big csv file (attached).
If I try to read it as a table with readtable, MatLab displays the error: "All lines of a text file must have the same number of delimiters".
I made a check for delimiters with medhan ravi code from https://it.mathworks.com/matlabcentral/answers/418855-how-do-i-ensure-that-the-number-of-delimiters-on-each-row-are-constant-when-reading-a-hige-csv-file and apparently all the records have the same number of delimiters...
I would like to split the file in 4 tables, that I can use for elaborating datas. as you can see, each table in the source file starts with character 'I', while the other rows starts with 'D'.
I have tried with this (implementing medhan ravi code):
fid=fopen('PUBLIC_PRICES_201911180000_20191119040539.CSV ','r'); % open the file
l=fgetl(fid); % read first line
i=1; % record counter
while ~feof(fid) % rest of file
l=fgetl(fid);
if ~startsWith(l,'I')
table{i}={table{i};l};
else
i=i+1;
table{i}={l}
end
end
I tried to concatenate rows with curly brackets but didn't work.
I would really appreciate any help,
thanks you all

採用された回答

Francesco Giuseppe Fornari
Francesco Giuseppe Fornari 2019 年 11 月 22 日
I solved this way:
fileID=fopen('path','r');
C=textscan(fileID,'%q','Delimiter','\n');
Index=find(contains(C{:},'I,'));
totalrows=size(C{1});
for i=1:(size(Index)-1)
D{i}=C{1}(Index(i):(Index(i+1)-1));
end
D{i+1}=C{1}(Index(i+1):totalrows);
text=char(D{1});
T=table;
titoli=strsplit(text(1,:),',');
titoli([20:21 23:29 31:37 39:45 47:53 55:61 63:67 73 75:77 79:96 ])=[];
for i=1:((size(text,1))-1)
T(i,:)=strsplit(text(i+1,:),',');
end
T.Properties.VariableNames=titoli;

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