matrix comparison and substitute value
1 回表示 (過去 30 日間)
古いコメントを表示
Hi, I have one matrix
A=[4 2 3
9 5 6]
I have another vector b=[1 0]. I want to compare the first column of A with b, and if the position in A correspondes to a 1 in b, then I would like to replace that value (4 multiply 0.99) and if 0, it will keep as it is . I was wondering is there any way to do that without executing nested for loops?TIA
0 件のコメント
回答 (1 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!