trouble with using isnan function

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Richard Silberstein
Richard Silberstein 2019 年 11 月 5 日
回答済み: Richard Silberstein 2019 年 11 月 5 日
Hi,
I have 51 complex arrays temp1(2X390X51). Now I know that all arrays except temp1(:,:,25) comprises valid numerical values.
And all the values in temp1(:,:,25) are described as NaN by matlab. When I use the following in the Command Window: isnan(temp1(2,1,25)) I get the correct Logical 1 ie true) which is correct.
However, when I put the same line: isnan(temp1(2,1,25)) in a loop, the expression yields Logical 0. (ie false, which it is not)
Can anyone tell me what I'm doing wrong?
Thanks
Richard
  2 件のコメント
the cyclist
the cyclist 2019 年 11 月 5 日
It would be much easier to diagnose the problem if you upload code and/or variables (in a *.mat file), using the paper clip icon.
James Tursa
James Tursa 2019 年 11 月 5 日
編集済み: James Tursa 2019 年 11 月 5 日
Likely the temp1 you are using in a loop differs from the temp1 you are using at the command line. I.e., something in your code is making them different before you do the compare.

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回答 (1 件)

Richard Silberstein
Richard Silberstein 2019 年 11 月 5 日
Thank you James and 'the cyclist',
I did appreciate your prompt input and suggestions.
I did find the source of my confusion, I mistook a processed array for an input array.
The processed array comprised NaN while the input array that caused the problem comprised complex zeros.
Thanks again,
Richard

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