calling more than 2 matrix for for loop

A =

8 9

15 39

23 14

18 2

13 17

40 18

14 39

38 42

x1= A([1,2,3,5,8],:)

x2= A([1,2,3,4,8],:)

x3=A([1,2,3,5,7],:)

x4=A([1,2,3,4,5,8],:)

can i have a for loop which can call x1, x2,x3,x4 in an order

[David Hill]

I am not sure what you mean, please explain more fully.

[sampath kumar punna]

x1 =[

8 9

15 39

23 14

13 17

38 42]

x2 =[

8 9

15 39

23 14

18 2

38 42]

x3 =[

8 9

15 39

23 14

13 17

14 39]

x4 =[

8 9

15 39

23 14

18 2

13 17

38 42]

i have 4 matrices i want to call each matrix to get divided by 2

which is something like this

for i=1: 4

y(i)= x(i)/2

end

but this for loop is is not working beacuse location of x1,x2,x3,x4 is not fixed.

Answer 1

[David Hill]

Why not make a cell array?

x{1}= A([1,2,3,5,8],:);
x{2}= A([1,2,3,4,8],:);
x{3}=A([1,2,3,5,7],:);
x{4}=A([1,2,3,4,5,8],:);
for i=1:4
    y{i}=x{i}/2;
end

[sampath kumar punna]

thanks for the answer but its not working

[David Hill]

Maybe I misunderstood you, it works for me and produces a cell array (y) having matrix elements that are the elements of x divided by 2.