Hi, I've found many similar questions relating the transformation from cell-array to 3D matrix, but none of the solutions worked for me (or I was unable to adapt the solutions for my problem)
I have a (20x1) cell array and each cell contains a 360x900 matrix. Optimally, the new 3D matrix has the dimension 900x20x360 but 360x900x20 would also work for me.
Thanks for your help!

 採用された回答

Daniel M
Daniel M 2019 年 10 月 19 日

0 投票

mycell = repmat({rand(360,900)},20,1);
% this is what you currently have
mat3D = permute(cat(3,mycell{:}),[2 3 1]);
whos mat3D % [900,20,360]

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeMultidimensional Arrays についてさらに検索

質問済み:

2019 年 10 月 19 日

回答済み:

2019 年 10 月 19 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by