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Create a matrix on the basis of other matrix

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luca
luca 2019 年 10 月 14 日
回答済み: Andrei Bobrov 2019 年 10 月 14 日
Hi given a matrix
M= [ 0 4 8 6;
0 0 0 6;
0 0 0 6;
2 0 0 0;
0 0 0 0;
0 0 0 1;
0 4 7 0;
5 3 0 0;
0 0 0 6;
0 0 0 6;];
I want to create a new matrix A that contain just the diversity, no matter of the order and with no zeros.
so in this case
A = [2 4 8 6;
5 3 7 1];
Someone can help me with the code?

採用された回答

Fabio Freschi
Fabio Freschi 2019 年 10 月 14 日
編集済み: Fabio Freschi 2019 年 10 月 14 日
Under the assumption that the "diversity" contains the same number of entries each row
for i = 1:size(M,2)
b(:,i) = unique(nonzeros(M(:,i)));
end
If each column can have different number of interest
b = arrayfun(@(i)unique(nonzeros(M(:,i))),1:size(M,2),'UniformOutput',false)
then you can access to the unique values of the jth row as
b{j}

その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2019 年 10 月 14 日
[~,j] = find(M);
C = accumarray(j,M(M ~= 0),[],@(x){unique(x,'stable')})
if all(diff(cellfun(@numel,C)) == 0)
C = [C{:}];
end

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