Place each dimension of matrix into a cell array

Given a matrix with 3 non-singleton dimensions, how can I place each 2d matrix (along dimension 1) into an element of a cell array?

Concretely:

Given

A(:,:,1) = [1 2; 3 4] A(:,:,2) = [5 6; 7 8]

How do you construct a cell array B such that

B{1} = [1 2; 3 4] B{2} = [5 6; 7 8]

Thanks! (I can write a for loop, but that seems awfully inefficient)

Answer 1

[Matt Fig]

B = squeeze(mat2cell(A,2,2,[1 1]))

This is probably quicker:

mat2cell(reshape(A,2,4),2,[2 2])

More generally:

A(:,:,1) = [1 2; 3 4;5 6;45 50]; 
A(:,:,2) = [7 8;9 10;11 12;13 14]; 
A(:,:,3) = [70 80;90 100;110 120;130 140];
S = size(A);
B = mat2cell(reshape(A,S(1),S(2)*S(3)),S(1),ones(1,S(3))*S(2))

[Fernando Duarte]

Great answer, short and effective.

Thank you Matt