Using DTW function in Matlab with euclidean metric for 2D data

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m qasim
m qasim 2019 年 9 月 21 日
コメント済み: Erik Jakobsson 2021 年 1 月 20 日
Hi iam using Matlab 2018a
When using DTW function for two single vectors on X and Y the DTW works good
but when using the 2D data as matrix input for DTW , the finction returns the absolute value for both metrics 'euclidean as well as absolute
X1=[3 7;5 9];
Y1=[4 5;2 6];
dist=dtw(X1,Y1,'euclidean')
& dtw(X1,Y1,'absolute')
both returns same answer
  1 件のコメント
Erik Jakobsson
Erik Jakobsson 2021 年 1 月 20 日
I have noticed this issue as well. It seems the function always returns the 1-norm, irrespective of the "metric" argument.

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