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choosing from numbers whose sum is X

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Matlabbey
Matlabbey 2012 年 9 月 11 日
hi all,
suppose i generate 1000 random numbers and want to pick five out of that 1000 so that the sum of the five numbers is 100. if there is no way so the sum equal to 100 then i will just re run it. it doesnt have to work always...thank you!!

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Matt Fig
Matt Fig 2012 年 9 月 11 日
編集済み: Matt Fig 2012 年 9 月 11 日
I suppose you mean integers, but you don't say....
N = round(randn(1,1000));
S = 0;
maxiter = 2e6;
cnt = 1;
while S~=5 & cnt<maxiter
R = ceil(rand(1,5)*1000);
S = sum(N(R));
cnt = cnt + 1;
end
Now we have the numbers, so look at them:
nums = N(R)
sum(nums)
  3 件のコメント
Matt Fig
Matt Fig 2012 年 9 月 11 日
編集済み: Matt Fig 2012 年 9 月 11 日
What do you mean, no fixed sum? I generated 100 random numbers and chose 5 whos sum is 5. If you need to change it to the sum being 100, then just use:
while S~=100
You might also like a different distribution. So:
N = round(randn(1,1000)*20);
N = randi(100,1,1000); % etc...
Matlabbey
Matlabbey 2012 年 9 月 11 日
sorry, you're right!! thank you!!

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その他の回答 (1 件)

Sean de Wolski
Sean de Wolski 2012 年 9 月 11 日
編集済み: Sean de Wolski 2012 年 9 月 11 日

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