Simulink bode diagram loop transfer with negative feedback

3 ビュー (過去 30 日間)
Rasmus Steffensen
Rasmus Steffensen 2019 年 8 月 19 日
編集済み: Enrique Babio 2021 年 6 月 11 日
Hi,
I am using the bode plot block in simulink, and want to get the open loop transfer function using the 'Loop transfer' configuration. The problem is that it returns the transfer function with positive feedback, and not the one with negative feedback. I.e. i want to as with the matlab equivalent function 'L = getLoopTransfer(T,Locations,sign)' to specify the sign to -1. Is it possible?
kind regards,
Rasmus.

回答 (1 件)

Nikhil Sonavane
Nikhil Sonavane 2019 年 8 月 22 日
You may refer to the tutorial video for more information on how to get the open loop transfer function.
  1 件のコメント
Enrique Babio
Enrique Babio 2021 年 6 月 11 日
編集済み: Enrique Babio 2021 年 6 月 11 日
Sure, the approach in the video works, but it defeats some of the the purpose of having the 'loop transfer' linearization setting available. That setting would seem the most useful for getting open loop transfer functions on the go from the closed loop diagram that already includes the negative feedback. See your own tutorial: analysis points
For example, I could set the 'loop transfer' point at an actuator model and then I get the margins at this point as a way to determine robustness against changes in its closed loop transfer function. What use cases does the current implementation address?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeClassical Control Design についてさらに検索

製品


リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by