obtaining the average value for a data set
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Hello, I have a data set which contains a value for a number of stations during some years (station, date, value). Data for some days is missing. I need to create a column with annual average value per station. I appreciate your help.
station date value average(yearly per station)
1 2001/1/1 2 2
1 2001/1/3 1 2
1 2001/1/5 3 2
2 2001/1/1 2 2.5
2 2001/1/4 3 2.5
1 2002/1/2 2 1.5
1 2002/1/6 1 1.5
2 2002/1/1 2 2.5
2 2002/1/2 3 2.5 . .
3 件のコメント
Azzi Abdelmalek
2012 年 9 月 4 日
編集済み: Azzi Abdelmalek
2012 年 9 月 4 日
can you specify the size of your data array, cell or .., how should the result looks like?
回答 (1 件)
Matt Tearle
2012 年 9 月 4 日
編集済み: Matt Tearle
2012 年 9 月 4 日
It looks like the fourth column is what you want to calculate. If so, this will do the job, assuming that you have the first three columns as station, date, and value (numeric vectors except date which is a cell array of strings)
% get the years from the date strings
dv = datevec(date);
year = dv(:,1);
% get all combinations of station & year
[stlist,yrlist] = meshgrid(unique(station),unique(year));
% allocate space for the calculated average
avg = zeros(size(station));
% loop over every station/year combination
for k = 1:numel(stlist)
% find the location of this combination in the data set
idx = (year == yrlist(k)) & (station == stlist(k));
% calculate the mean
avg(idx) = mean(value(idx));
end
This could probably be simplified with prior knowledge of the station numbers and years.
EDIT TO ADD: Given your comment above, ignore the first couple of lines -- you already have year.
3 件のコメント
Sean de Wolski
2012 年 9 月 6 日
Why would you want to avoid the loop? The loop will likely be very fast and is easy to read/understand.
Matt Tearle
2012 年 9 月 6 日
Possibly, although I doubt it will be neat. More importantly, why do you want to avoid loops?
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