specific pattern from the file name
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I want to extract the project number from the file name
example the file fame is: 'abcdd-22_Z12'
the project number should be Z12 for sure it is dynamic name could in the next file name Z11 for intance.
which expression I should use
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採用された回答
per isakson
2019 年 7 月 26 日
編集済み: per isakson
2019 年 7 月 26 日
These statements
%%
chr = 'abcdd-22_Z12';
cac = regexp( chr, '(?<=_)Z\d{2}', 'match' );
cac{:}
return
ans =
'Z12'
This regex, '(?<=_)Z\d{2}', matches a literal "Z" followed by two digits, which is preceded by underscore.
その他の回答 (1 件)
Walter Roberson
2019 年 7 月 26 日
[~, basename, ext] = fileparts(FileName);
parts = strsplit(basename, '_');
project = parts{end};
In some cases this can be simplified: for example if the directory and extension are already removed from FileName then
project = regexp(FileName, '(?<=_).*', 'match');
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