I have for instance a vector called A:
And another vector called B:
And another vector called C:
I'd like another vector D which is:
  • same length as vector B and C; and
  • will show a 1 if:
  • there is a match between vector A and vector B (else a 0); and
  • the corresponding matched value in vector C is less than or equal to 30.
For instance:
B(1) = 149.1408, A(1) = 149.1408, C(1) = 5 <= 30 so D(1) = 1 etc etc.
Would also like a vector E (size of A) counting occurrences from vector D.

回答 (1 件)

Star Strider
Star Strider 2019 年 6 月 8 日

0 投票

The ismembertol (link) function is likely appropriate. (Another option is the ismember (link) function, althoughit is likely not appropriate here.)

6 件のコメント

Patrick Rungrugeecharoen
Patrick Rungrugeecharoen 2019 年 6 月 8 日
I've just ammended the question to be more specific for your reference. Thanks.
Star Strider
Star Strider 2019 年 6 月 8 日
The first output of either function is a logical vector. You can then use the and,& (link) function to logically ‘and’ the two vectors with a logical vector testing ‘C’. The & of those vectors will produce a logical vector describing ‘D’.
Patrick Rungrugeecharoen
Patrick Rungrugeecharoen 2019 年 6 月 8 日
Just tried this but 'and' is for vectors of same dimensions whereas mine here is not.
Star Strider
Star Strider 2019 年 6 月 8 日
I got the impression that all three vectors, ‘A’. ‘B’ and ‘C’ were the same length. If that is not true, then you can only match the elements that correspond to the shortest vector.
Patrick Rungrugeecharoen
Patrick Rungrugeecharoen 2019 年 6 月 8 日
Yes, hence the little pickle I'm in. Not too sure how to resolve this issue. I figured two for loops would work but it stops at the shorter of the two.
Star Strider
Star Strider 2019 年 6 月 8 日
You actually don’t need any loops. You can do everything with the logical vectors.
You have to choose how to deal with the vectors not having the same numbers of elements. I can’t resolve that.

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