How to get coefficients of triangular functions in an expression

1 回表示 (過去 30 日間)

Lei LIU 2019 年 5 月 21 日

for example, X=k*sin(p1 + x*t) + c*sin(2*p1 + 2*x*t)

when I used 'coeffs' as:

[P, T]=coeffs(X,'sincos')

The result is:

P = k*sin(p1 + x*t) + c*sin(2*p1 + 2*x*t)

T =1

Actually, I want to get the coeffients of X as:

P=[k, c]

T=[sin(p1 + x*t), sin(2*p1 + 2*x*t)]

How can I do to get the desired result?

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