Problem plotting bode for a 2nd order system
11 ビュー (過去 30 日間)
古いコメントを表示
Hi, I'm getting started with simulink, I tried to simulate a 2nd order mass spring system but the bode plot seems odd :

K1 = 50
K=1/m1 = 1
I don't know which linear analysis point to choose
This system should have a resonance iif c1 < 1/sqrt(2)
If I choose open loop output, then bode NEVER shows a resonance no matter what c1 is.
If i choose output measurement, bode shows me a resonance if c1 < 9 (instead of 1/sqrt(2))
So, which analysis point should i use ?
4 件のコメント
Jan
2019 年 5 月 15 日
編集済み: Jan
2019 年 5 月 15 日
@François Blas: Again: Please stop bumping your question by posting pseudo-answers. This behavior is not liked in this forum and it is possible, that you question is ignored in consequence.
Counting the time since you've asked your question looks taunting.
採用された回答
Sulaymon Eshkabilov
2019 年 5 月 13 日
編集済み: Sulaymon Eshkabilov
2019 年 5 月 13 日
Hi Francois,
I have tested and simulated your example and it works as it has to w.r.t. the values of M1, K1, C1. In fact, for your data: K1 = 50, M1 =1, C1 = 2 (e.g). The resonant occurs at the frequency of sqrt(50/1) (approximately 7 Hz) and not @ sqrt(2) as you were anticipating. The selection of output measurement, is the right one. Here is my tested Simulink model. It is in fact correct that the resonant occurs at sqrt(50) => 7Hz that can be seen from the TF of SMD: 1/ (M1s^2+C1s+K1) ==> resonant freq: = sqrt(K1/M1).
Good luck.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で General Applications についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!