How many zeros do I have before a specific sting variable?

1 回表示 (過去 30 日間)
antonet
antonet 2012 年 8 月 15 日
Dear all
I have
A={
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
[0]
' b1'
' b1'
' b1'
' b1'
' b1'
'b1'
' b1'
[0]
[0]
[0]
'b1'
' b1'}
I have this cell vector. This vector has a characteristic. Immediately after the first zeros the letter 'b1' begins. So I would like to count the zeros before the first 'b1' that starts to appear in this vector. In this case I have 39 zeros. Is it possible to calculate this number using a Matlab code?
thanks

採用された回答

Andrei Bobrov
Andrei Bobrov 2012 年 8 月 15 日
yourzeros = find(cellfun(@ischar,A),1,'first')-1;

その他の回答 (3 件)

Matt Fig
Matt Fig 2012 年 8 月 15 日
編集済み: Matt Fig 2012 年 8 月 15 日
T = strfind(cellfun(@(x) ~x(1),A).',[1 0])
Notice that T will show you the index of every zero that is followed by a nonzero. So you want T(1).

Azzi Abdelmalek
Azzi Abdelmalek 2012 年 8 月 15 日
min(find(cellfun(@(x) ~isnumeric(x),A)))-1

Oleg Komarov
Oleg Komarov 2012 年 8 月 15 日
Another solution:
pos = strfind([A{:}],'b')-1
pos(1)
  2 件のコメント
Andrei Bobrov
Andrei Bobrov 2012 年 8 月 16 日
Hi Oleg! may be in this case so?
pos = strfind([A{:}],' ')-1
pos(1)
Oleg Komarov
Oleg Komarov 2012 年 8 月 16 日
I assumed the ' ' was a typing error :)

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