How can I set a reference value in PID in Matlab code/script?

12 ビュー (過去 30 日間)
SYED IMTIAZ ALI SHAH
SYED IMTIAZ ALI SHAH 2019 年 4 月 18 日
回答済み: Raj 2019 年 4 月 19 日
For example I have the following code which also include Transfer function. When I run this program, I want this program to tune my transfer function to a reference point of 0.1 however I have no clue how to do it.
clear all
clc
syms numerator denomenator Gp H Ts Gc Ka
numerator = [1];
denomenator = [1 0.3 0];
Gp = tf(numerator, denomenator)
H = [1];
Ts = feedback(Gp, H)
%%
Kp = 16;
Ki = 0;
Kd = 20;
Gc = pid(Kp, Ki, Kd)
Ka = 2;
Mc = feedback(Ka*Gc*Gp, H)
step(Mc)
hold on
grid on

回答 (1 件)

Raj
Raj 2019 年 4 月 19 日
Since you have put "step(Mc)" the closed loop system Mc is showing step response plot and tracking the value '1'.
Your requirement is for your closed loop system to track a reference of 0.1. Use this:
t = 0:0.1:10; %Simulation runs for 10 seconds with 0.1 sec sampling time
u_ref = 0.1*ones(size(t)); %Reference signal
u_input=zeros(size(t)); % input signal to the closed loop system
% now feed the difference of input and reference signal to your closed loop system and see the time response.
% The closed loop system will track and settle at the reference signal.
lsim(Mc,u_ref-u_input,t)
Hope this is what you are asking. If not please elaborate on your problem statement.

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