Fixe the number of digit when creating matrix

2 ビュー (過去 30 日間)
Aurelie
Aurelie 2012 年 8 月 9 日
I try to create a matrix with 2 objects: A a list of numbers with 4 digits B a matrix of numbers with 0 digits
I used M = [A, B]
But when I do that I lose the 4 digits of A and all numbers in my matrix have 0 digits. How to keep the numbers of digits of A while creating the matrix?
Thanks
  2 件のコメント
Matt Fig
Matt Fig 2012 年 8 月 9 日
Give an example of the numbers you mean. Are you mixing types? What does
whos A B
show?
Aurelie
Aurelie 2012 年 8 月 9 日
Name Size Bytes Class Attributes
A 2420000x1 19360000 double
B 2420000x16 154880000 int32
A= 800.090909093618 800.181818187237 800.272727280855 800.363636374474 800.454545468092 800.545454561710 800.636363655329 800.727272748947 800.818181842566 ...
B= 0 0 44 0 7 16 0 31 3 0 12 0 0 3 0 0 0 0 0 0 0 0 36 0 0 28 0...
M= 800 0 0 44 800 0 7 16 800 0 31 3 800 0 12 0 800 0 3 0 801 0 0 0 801 0 0 0 801 0 36 0 801 0 28 0...
It is rounding A with 0 digits

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Matt Fig
Matt Fig 2012 年 8 月 9 日
That is what I thought... Concatenating types like this will cause MATLAB to make M into an int32
M = [A,double(B)]
  1 件のコメント
Aurelie
Aurelie 2012 年 8 月 9 日
Yes it works now, I just started ti use matlab and now I think I need to learn about class of variables, thanks

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