フィルターのクリア

plot symbolic function real part

2 ビュー (過去 30 日間)
john_arle
john_arle 2019 年 3 月 31 日
コメント済み: Star Strider 2019 年 3 月 31 日
Hello there,
I would like to plot the real part of this symbolic function I have just solved.
Parameters 'a' and 'e' are varying between 5 and 9, and 0.05 and 0.15 respectively.
Unfortunately, it does not work.
Here you go with my code ( solution is a ratio of sum of Bessel functions of order zero).
clc
clear
set(groot,'DefaultAxesFontSize',14)
set(groot,'DefaultLineLineWidth',1.5)
syms a e
A = [besselj(0,-1i*a*e), bessely(0,-1i*a*e); ...
besselj(0,-1i*a), bessely(0,-1i*a)];
b = [-1; -1];
X = linsolve(A, b);
disp(X)
a = linspace(5,9);
e = linspace(0.05, 0.15);
plot(a, e, X)

採用された回答

Star Strider
Star Strider 2019 年 3 月 31 日
You are plotting a function of two variables, so you need to use a plot that accommodates them, and that your function is symbolic.
Try this:
syms a e
A = [besselj(0,-1i*a*e), bessely(0,-1i*a*e); ...
besselj(0,-1i*a), bessely(0,-1i*a)];
b = [-1; -1];
X = linsolve(A, b);
disp(X)
a = linspace(5,9);
e = linspace(0.05, 0.15);
fsurf(real(X), [5 9, 0.05 0.15])
xlabel('a')
ylabel('e')
Experiment to get the result you want.
  2 件のコメント
john_arle
john_arle 2019 年 3 月 31 日
Thank you. Any other options that fsurf that I can try?
regards,
Andrea.
Star Strider
Star Strider 2019 年 3 月 31 日
As always, my plesure.
There are several 3D plots that will probably work with your system. See the documentation on fcontour (link), fmesh (link), and fplot3 (link).

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by