Integrate over time return corresponding y value for predefined volume

10 ビュー (過去 30 日間)
Fer Gug
Fer Gug 2019 年 3 月 29 日
This graph describes the problem well.
Given:
  • time series with x (time [s]) and y (here discharge [m³/s])
  • V1 = a value in the same dimension / unit as the result of the integration, smaller than the integral. Here a small volume [m³]
Needed:
  • The y[m³/s] value, which leads to V1 if integration (minus the y values smaller) is started there.
The V1 must be placed around the peak.
I'm rather new to MATLAB.
I think this must be an iterative process, where also a the fitting criteria (and the degree of exactness) must be set by the user.
All in all an intersting task. Till now I haven't found a way to start; besides the pure integration.
wave.png

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