I ve been trying to create a Fibonacci Sequence in which ratio of the adjacent values converge to 0.001. Here is the code I've written so far:
clc
clear
x = input('Please enter the first number in the series:');
y = input('Please enter the second number in the series:');
s(1) = x;
s(2) = y;
k = 3;
while abs(s(k)./s(k-1) - s(k-1)./s(k-2))>0.001
s(k) = s(k-1) + s(k-2)
k = k+1;
end
disp(s)
But when I run the code, it says; Index exceeds the number of array elements (2)
Error is on the eighth line.

3 件のコメント

Kevin Phung
Kevin Phung 2019 年 3 月 25 日
there is an error because you have not defined what s(3) is.
Kaan Uçar
Kaan Uçar 2019 年 3 月 25 日
I defined s(3) as x + y and and still get the error. This time in parantheses it says 3 instead of 2.
Kevin Phung
Kevin Phung 2019 年 3 月 25 日
編集済み: Kevin Phung 2019 年 3 月 25 日
ok, and where is that in your code? What is see is that you've set s(1) and s(2) to be the user input.
Youve made k a constant 3, and your while loop CONDITION:
while abs(s(k)./s(k-1) - s(k-1)./s(k-2))>0.001
starts with s(k) which is s(3), and that does not exist.

サインインしてコメントする。

 採用された回答

Raghunandan V
Raghunandan V 2019 年 3 月 26 日

1 投票

Hi,
I just shuffled the code a bit. Check this:
clc
clear
x = input('Please enter the first number in the series:');
y = input('Please enter the second number in the series:');
s(1) = x;
s(2) = y;
k = 3;
Cond =1; % intialize the condition
while Cond > 0.001
s(k) = s(k-1) + s(k-2);
Cond = abs(s(k)/s(k-1) - s(k-1)/s(k-2));
k = k+1;
end
disp(s)

1 件のコメント

Kaan Uçar
Kaan Uçar 2019 年 4 月 13 日
Sorry for the late response. I got the problem fixed. Thank you for your helps.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File Exchange で Matrix Indexing についてさらに検索

製品

リリース

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by