Is it possible to detect and replace abnormal/wrong numbers in an array?

5 ビュー (過去 30 日間)
Rikke
Rikke 2019 年 3 月 20 日
コメント済み: Chris Turnes 2019 年 3 月 21 日
I have a dataset which is an array containing values, and which are plotted in the figure below. A section of the array for the figure is: A = [.... 25.9, 25.9, 26.2, 27, 28, 29, 29.3, 29.6, 3, 30.4, 30.5, 30.4, 30.3, 30.3, ....]; Here is number 3 an abnormality in the array. Is it possible to detect these abnormal numbers and replace them with the average value of the number before and after? So for the number 3 in A I want it to be (29.6+30.4)/2.
figure2.jpg

採用された回答

Kevin Phung
Kevin Phung 2019 年 3 月 20 日
A = [25.9, 25.9, 26.2, 27, 28, 29, 29.3, 29.6, 3, 30.4, 30.5, 30.4, 30.3, 30.3]
abnorm =mean(A) - 3*std(A); % you can set however many standard deviations to constitute 'abnormal'
n = find(A<abnorm); %locations of abnormals
for i = 1:numel(n)
if or(n(i) == 1, n(i)==numel(A)) %if first or last index, replace with NaN;
A(n(i)) = nan;
else
A(n(i)) = (A(n(i) - 1) + A(n(i) + 1)) / 2;
end
end
A(isnan(A)) = []; %remove the endpoints that are NaN
let me know if this works for you
  7 件のコメント
Kevin Phung
Kevin Phung 2019 年 3 月 20 日
編集済み: Kevin Phung 2019 年 3 月 20 日
happy to help!
edit: if number of lines of code is important to you at all, you can actually condense the first 3 lines to one
n = find(isoutlier(A,'movmedian',5)); %locations of abnormals
for i = 1:numel(n)
if or(n(i) == 1, n(i)==numel(A)) %if first or last index, replace with NaN;
A(n(i)) = nan;
else
A(n(i)) = (A(n(i) - 1) + A(n(i) + 1)) / 2;
end
end
A(isnan(A)) = []; %remove the endpoints that are NaN
Rikke
Rikke 2019 年 3 月 20 日
Aha, perfect!

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2019 年 3 月 20 日
  2 件のコメント
Rikke
Rikke 2019 年 3 月 20 日
Thanks!
Chris Turnes
Chris Turnes 2019 年 3 月 21 日
You may also be interested in the filloutliers function, which lets you not only identify outliers but replace them as well.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrices and Arrays についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by