split a diagonal matrix
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v = [2 1 4];
D = diag(v)
Having a diagonal matrix, i wanted to split the diagonal matrix as below
M1 = [
2 0 0
0 0 0
0 0 0]
M2 = [
0 0 0
0 1 0
0 0 0]
M3 = [
0 0 0
0 0 0
0 0 4]
working for any dimension diagonal matrix
1 件のコメント
Jos (10584)
2019 年 3 月 18 日
What do you mean by "working for any dimension diagonal matrix" ?
Any number of elements in V? In that case, see my answer below.
採用された回答
KSSV
2019 年 3 月 18 日
v = [2 1 4];
nx = length(v) ;
M = zeros(nx,nx,nx) ;
for i = 1:nx
M(i,i,i) = v(i) ;
end
0 件のコメント
その他の回答 (1 件)
Jos (10584)
2019 年 3 月 18 日
Having a vector V with any number of elements, this does the job:
V = [2 1 4]
n = numel(V) ;
M = zeros(n,n,n) ;
M(linspace(1, n^3, n)) = V
If you have a diagonal matrix D, use V = diag(D) first.
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