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Multiple Variable For Loop

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Adam Parry
Adam Parry 2012 年 7 月 31 日
Hi
I have so far written this for loop
for i = 1:VgStep
for start = 1:VgStep:endPoint-VgStep+1
for step = VgStep:VgStep:endPoint
Vd{j}{i} = x(start:step);
Id{j}{i} = y(start:step);
end
end
end
I appologise for not explaining what all the terms are, but what I need is combine all those for's into one, because I end up just getting the same value for all my Vd{j}{i} terms
I'll explain better if it is needed
  4 件のコメント
Adam Parry
Adam Parry 2012 年 7 月 31 日
編集済み: Adam Parry 2012 年 7 月 31 日
ah ok.
so here is some data
x y Vg
0 1 0
-1 2 0
-2 3 0
0 4 -1
-1 5 -1
-2 6 -1
0 7 -2
-1 8 -2
-2 9 -2
I need to split the data into three separate arrays
so I want
Vd{1}{1} = [0,-1,-2] Id{1}{1} = [1,2,3]
Vd{1}{2} = [0,-1,-2] Id{1}{2} = [4,5,6]
etc.
but i realised that the inside loops all finish before i can loop over to start a new cell.
How can I prevent this?
Walter Roberson
Walter Roberson 2012 年 7 月 31 日
John, neither start nor step are reserved words. See http://www.mathworks.com/help/techdoc/ref/iskeyword.html

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採用された回答

Albert Yam
Albert Yam 2012 年 7 月 31 日
In the code posted, you do not have 'j' (this might be elsewhere in your code), in your example, not even sure why you need it.
Since you know what your step size is, you don't need to loop it, the way it is now, seems incorrect. This is what I see from your start:stop. When start > stop , you will get an empty index.
1:3, 1:6, 1:9, 4:3, 4:6, 4:9, 7:3 (error), 7:6 (error), 7:9
Do you understand how the following works?
i = 1;
for start = 1:VgStep:length(Vg) %what does this count?
Vd{i} = x(start:start+2); %try to understand the indexing here
Id{i} = y(start:start+2);
i=i+1; %how is this affected by 'start'?
end
  1 件のコメント
Adam Parry
Adam Parry 2012 年 7 月 31 日
Thank you
This is exactly what i was looking for

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