A simple question about undefined function error
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Hello,
Before i ask my question i want to mention that i am beginner level in matlab.
I wrote in matlab a simple program which is given below:
function [ output_args ] = Untitled( input_args )
for i=1:6
for j=1:30
k=1:24;
if 6<=k<17
if ruzgaruretimi(k,j)>sulamagider(k,j)
sebekein==sebekein
elseif ruzgaruretimi(k,j)<sulamagider(k,j)
if sdepo>0
sebekein==sebekein
sdepo==sdepo-1
elseif sdepo==0
sebekein==sebekein+15.708
end
end
end
end
end
end
I defined all veriables but i still get this error message:
Undefined function 'ruzgaruretimi' for input arguments of type 'double'.
Error in dnm (line 6)
if ruzgaruretimi(k,j)>sulamagider(k,j)
How can i solve it?
regards
1 件のコメント
Jan
2012 年 7 月 31 日
Variables are assigned by "=", while "==" compares variables. sebekein==sebekein replies TRUE for all elements - I assume it is meaningless actually.
採用された回答
その他の回答 (2 件)
Honglei Chen
2012 年 7 月 31 日
You need to make sure that the function ruzgaruretimi are on your path. It should also expect double inputs. If it does, try to do
rehash toolbox
to refresh your toolbox cache.
Wayne King
2012 年 7 月 31 日
0 投票
Have you defined this variable inside the function? Having the variable in your MATLAB workspace is not sufficient.
You could declare ruzgaruretimi as a global variable, but I think it is probably better to either define it inside your function, or pass that variable to your function as an input argument.
1 件のコメント
Wayne King
2012 年 7 月 31 日
Sorry, if it is a function, then what Honglei suggested is correct. I may have misunderstood that ruzgaruretimi is a matrix. If it is a matrix, then you have to make it a global variable, define it inside the function, or pass it as an input argument.
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