Any idea why all([]) is true while any([]) is false
2 ビュー (過去 30 日間)
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>> all([])
ans =
1
>> any([])
ans =
0
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the cyclist
2012 年 7 月 29 日
I can't say I know definitively, but I expect that one reason is for consistency when taking the union of sets with the empty set. For example, one would want
all(union(true,[]))
to be true, and also
any(union(false,[]))
to be false. The definitions in your question make sense in that context.
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