How can I convert a double array into a timestamp array?

I have an array of double like:

ora: [737426.687937060 737426.687937141 737426.687937176 etc....]

I want to get an array like:

time:[16:30:37:762 16:30:37:769 16:30:37:772]

How can i do??

Answer 1

[Stephan]

Hi,

use:

B = datestr(A, 'HH:MM:SS.FFF')

B =
  3×12 char array
    '16:30:37.762'
    '16:30:37.769'
    '16:30:37.772'

to get it as datestring - or (better):

C = datetime(datestr(A, 'HH:MM:SS.FFF'),'InputFormat','HH:mm:ss.SSS','Format','HH:mm:ss.SSS')

C = 
  3×1 datetime array
   16:30:37.762
   16:30:37.769
   16:30:37.772

to get it as datetime-type.

Best regards

Stephan

[Steven Lord]

There's no need to take a detour through datestr to get these as a datetime array.

A = [737426.687937060 737426.687937141 737426.687937176 ]
D = datetime(A, 'ConvertFrom', 'datenum', 'Format', 'HH:mm:ss.SSS')

Alternately if you want them as a duration (time after midnight) you can do this using dateshift.

D2 = D - dateshift(D, 'start', 'day');
D2.Format = 'hh:mm:ss.SSS'

[Stephan]

Nice!

[Guido Pastore]

thank you so much!

[Peter Perkins]

Alternatively, timeofday(D) would also convert to a duration.