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How to interpolate a value between two values in an array?

12 ビュー (過去 30 日間)
Arman Kam
Arman Kam 2012 年 7 月 26 日
Hi,i have an array named sumNy. the content of sumNy gives me Ny and the number of it's cells show me corresponding accelerations. now i have a specified Ny that is between two Ny s in my sumNy array, and i want to obtain it's corresponding acceleration.
i wrote this code but i dont know why it is not working
for i=1:150
if i==1
y=0;
elseif sumNy1(1,i-1)<=(1/475) & sumNy1(1,i)>=(1/475)
y=(((1/475)-sumNy1(1,i))/(sumNy1(1,i-1)-sumNy1(1,i)))*(i-1)+(1-(((1/475)- sumNy1(1,i))/(sumNy1(1,i-1)-sumNy1(1,i))))*(i);
end
end
please help me
Thanks
  2 件のコメント
Arman Kam
Arman Kam 2012 年 7 月 26 日
i must say that (1/475) is my specified Ny
Arman Kam
Arman Kam 2012 年 7 月 26 日
and by the way, there is two Ny s in my array that the specified Ny (1/475) place between them, so that is not why everytime i run this code it gives me y=0 !

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回答 (2 件)

Wayne King
Wayne King 2012 年 7 月 26 日
Have you tried interp1?
For example:
t = 0:10; x = sin(t);
tnew = 0:.25:10;
xnew = interp1(t,x,tnew);
plot(t,x,'o',tnew,xnew)
  2 件のコメント
Arman Kam
Arman Kam 2012 年 7 月 26 日
i dont know what to put as a function in interp1 that gives me linear interpolation.
Arman Kam
Arman Kam 2012 年 7 月 26 日
i think the code i wrote do what i want but everytime i try this code the value of y will be zero!
would you please help me whats wrong with this code?!

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Arman Kam
Arman Kam 2012 年 7 月 26 日
sorry friends, i just find out my horrible mistake!
but still if you have a better way to do this please tell me

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