vector function takes vector input ?

Hello !
I am having truble inserting vectors as an input to a function that is a vector
what I did is
I defined a function as
gradient=@(x) [1;x;x^2;x^3];
then I need to input a vector to it. like this
gradient([2 ;3 ; 4])
or
gradient([2 3 4])
so the result I am hoping for is a matrix where each column represent a function (1,x,x^2,x^3)
and each row is the value of the function at each point in the input vector.
so it would be some thing like:
1 2 4 8
1 3 9 27
1 4 16 46
I have done this using loop. but since the data I am dealing with is large this takes so long and I would brefer a method that does it in a vector form.

 採用された回答

Star Strider
Star Strider 2019 年 2 月 10 日

1 投票

First, gradient is a quite useful built-in MATLAB function, so name your function something different.
Second, your function needs some help.
Try this:
myGradient = @(x) [ones(size(x(:))), x(:), x(:).^2, x(:).^3];
Y = myGradient([2 3 4])
I will leave it to you to explore the details of colon operator single-indexing (it forces ‘x’ here to be a column vector), and the necessity to use the ones function.
Y =
1 2 4 8
1 3 9 27
1 4 16 64

4 件のコメント

Nora Khaled
Nora Khaled 2019 年 2 月 10 日
Thank you very much !
this worked very well and way much faster that my original loop.
Star Strider
Star Strider 2019 年 2 月 10 日
My pleasure!
If my Answer helped you solve your problem, please Accept it!
Nora Khaled
Nora Khaled 2019 年 2 月 13 日
sorry did not know I had a choice of accepting the answer.
And again, Thank you!
Star Strider
Star Strider 2019 年 2 月 13 日
As always, my pleasure.
Thank you!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeLoops and Conditional Statements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by