Newton's Method for finding zeros
19 ビュー (過去 30 日間)
古いコメントを表示
I am trying to divide the function f(x0) by its derivitive df(x0), but Matlab keeps giving me errors about dividing by df(x0). My code is the following:
clear;
syms x f(x) f df(x) df
f = @(x) x.^2 - 3;
df = diff(f,x);
x0 = 1;
N = 6;
epsilon = 0.000001;
for t = 1:N
j = x0;
x0 = x0 - f(x0)/df(x0);
end
disp(x0)
0 件のコメント
回答 (1 件)
Geoff Hayes
2019 年 2 月 7 日
Lucas - what errors are you observing? Please copy and paste the full error message to your question. Do you need to use the Symbolic Toolbox? Can't you define df as just
df = @(x)2*x;
Note how your code isn't using epsilon. How are you supposed to be using this value?
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Symbolic Math Toolbox についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!