Check if filename is valid.
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Hi, is there a native function or a simple code to check if a user-typed filename is valid for saving a file? (In that it doesn't contain illegal characters like /\":?<>|, etc.)
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採用された回答
Sean de Wolski
2012 年 7 月 20 日
regexp it!
4 件のコメント
Jason Nicholson
2014 年 2 月 14 日
This code snippet will not work unless you check if it is empty.
if ~isempty(regexp(filename, '[/\*:?"<>|]', 'once'))
%Do something
end
Voss
2023 年 12 月 19 日
編集済み: Voss
2023 年 12 月 19 日
You need to escape the backslash in the regular expression for that to work right:
~isempty(regexp('file\name','[/\*:?"<>|]', 'once')) % no match
~isempty(regexp('file\name','[/\\*:?"<>|]', 'once')) % match
Of course, on Windows, if absolute or relative path names are allowed, then backslash is a valid character, and if absolute path names are allowed, then colon is a valid character. On Mac/Linux, if absolute or relative path names are allowed, then slash is a valid character.
その他の回答 (5 件)
Daniel Shub
2012 年 7 月 23 日
A long time ago, probably Windows 95 on a FAT16 harddisk, I started using the following:
regexp(fname, ['^(?!^(PRN|AUX|CLOCK\$|NUL|CON|COM\d|LPT\d|\..*)', ...
'(\..+)?$)[^\x00-\x1f\\?*:\"><|/]+$'], 'once'));
At that time, Windows had the most restrictive file name conventions. I am not sure what the rules are now. You also should check for the length of the path and the total number of characters in the file name.
1 件のコメント
Jan
2012 年 7 月 23 日
Windows 7: Either 260 characters, or start with //?/ and 32767 characters, while each folder can have up to 255 characters. The later works for most of the API-functions, but not e.g. for the Windows Explorer. Moving a file name with a long name to the RecycleBin fails also. The backup program and server based tools might fail also. Therefore I'd prefer the dull limit of 260 characters (including "C\:" and a trailing terminator '\0')!).
ola bayo
2017 年 10 月 16 日
編集済み: Walter Roberson
2017 年 10 月 16 日
Which following is a valid file name in MATLAB?
A) lab 2
B) lab2
C) lab-2
D) 2lab
E) LAB 2
1 件のコメント
Walter Roberson
2017 年 10 月 16 日
For the question as phrased: all of them. For a slightly different question, the answer would be fairly different.
Thomas
2017 年 12 月 1 日
If you do not want to use UIputfile, another option is fopen. fileID = fopen(filename,'w') if fopen cannot open the file, then fileID is -1.
0 件のコメント
Daniele Busi
2020 年 2 月 24 日
function bool = isLegalPath(str)
bool = true;
try
java.io.File(str).toPath;
catch
bool = false;
end
end
0 件のコメント
George Abrahams
2023 年 12 月 19 日
編集済み: George Abrahams
2023 年 12 月 19 日
Like @Daniele Busi's answer, it's based on java.io.File().toPath, which is more robust than anything we'll build ourselves, but isvalidpath also provides:
- The option to validate that the path refers to a file, rather than a directory, or vice versa.
- The option to validate that the file extension matches a given set, for example, that the path refers to an image.
- Human readable feedback, in case the validation fails, for example, a warning that the path lacks a filename or contains an illegal character.
0 件のコメント
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