How to apply hatched region to a polar map

I have a polar contour map using the mapping toolbox (see code below) that I would like to add a hatched region to, in order to show significance.

load coastlines
axesm('stereo','Origin',[-90 0],'MapLatLimit',[-90 -30]) 
framem on; 
gridm on; 
setm(gca,'MLabelParallel',-20)
pcolorm(latmesh(1:48,:),lonmesh(1:48,:),DataZ')
shading interp;
geoshow(coastlat,coastlon)
axis off
set(gca,'xtick',[],'ytick',[])
title('Z','fontsize',14)
set(gca,'FontSize',12)
caxis([-15,15])
colormap redblue

I am able to get the desired hatched region on a normal contour plot (See below).

figure(2);
[C,h]=contourf(latmesh,Ymesh,DataZ)
set(h,'linecolor','none')
hold on
box on
title('Y','fontsize',14)
set(gca,'FontSize',12)
caxis([-6,6])
colormap redblue
xlabel('lat (°)')

figure(2);
[c1,h1]=contourf(latmesh,Ymesh,DataZsig,[2.5 2.5]-10);
set(h1,'linestyle','none','Tag','HatchingRegion');
ax1=gca;
hp=findobj(ax1,'Tag','HatchingRegion');
set(h1,'linestyle','none');

However, When I try to use this method with the polar contour map, it does not work.

Does anyone have any suggestions on how to make this work?

Thank you!

Answer 1

[Chad Greene]

For anyone who wants to do this with Antarctic Mapping Tools, you may be able to use my stipple function. For a lat,lon grid and corresponding mask, just convert lat,lon to x,y and then use stipple like this:

[x,y] = ll2ps(lat,lon); 
stipple(x,y,mask)

Answer 2

[Mark Brandon]

Hi Holly,

What's your latmesh, longmesh and Ymesh?

Also you're plotting Antarctica. Do you use the Antarctic Mapping Tools toolbox?

Mark

[HA]

Hi Mark,

The mesh variables are grids of lat and lon, and for the one that works it is a lat and height grid. I think the problem is in the difference between contourf pcolourm.

Yes, I originall did the polar maps with the Antarctic Mapping toolbox, but found the method above to give me better plots. When I used the Antarctic Mapping toolbox I had simialr problems with plotting hatched markings (unable to call upon h1 as I am in the plot that works).

Holly

[Mark Brandon]

What a drag. Sorry not easy to solve.