フィルターのクリア

InputParser and function handle

1 回表示 (過去 30 日間)
Anon
Anon 2012 年 7 月 18 日
Hi,
I want to use the InputParser Class to check the inputs of a function. Basically my function looks like this
function a = myfun(b,varargin)
p = inputParser;
addRequired(p,'b',@isnumeric);
addOptional(p,'fun',@mean,@(x) isa(x,'function_handle'));
parse(p,b,varargin);
a = p.Results.fun(p.Results.b);
If I call this function, say with
a = myfun(rand(10,1),'fun',@mean)
Matlab throws an error saying
Error using myfun (line 8)
Argument 'fun' failed validation @(x)isa(x,'function_handle').
What am I doing wrong and what is the best way to pass a function handle through the inputParser?
Regards, Anon

回答 (1 件)

Wolfgang
Wolfgang 2013 年 3 月 25 日
You have to write:
parse(p,b,varargin{:});
In your case, the function handle is presented to the parser as part of a cell array (varargin) so it doesn't recognize it correctly.
  1 件のコメント
Bjorn Gustavsson
Bjorn Gustavsson 2013 年 8 月 7 日
(I just ran into the same problem as Anon.) That varargin is a cell-array I understand, but shouldn't varargin{:} be the list of its contens, and that list is what the parse function should see?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeArgument Definitions についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by