matlab coder error Directly accessing field or property of nonscalar struct or object not supported for code generation.

22 ビュー (過去 30 日間)
This works in Matlab but not in Coder, Why?
s1=string({OPS_FLT(:).ACFT_ID})
s2=OPS_FLT(2).ACFT_ID
uuindex=find(strcmpi(s1,s2))
My array is defineded as:
OPS_FLT(1).ACFT_ID="apple"
OPS_FLT(2).ACFT_ID="orange"
I need to find orange from the array but the code has to be compatible in coder. It says: Directly accessing field or property of nonscalar struct or object not supported for code generation in ({OPS_FLT(:).ACFT_ID})
  1 件のコメント
cui,xingxing
cui,xingxing 2023 年 4 月 6 日
It is hoped that future versions will support this feature, for example, the current R2023a supports "end+1" C/C++ code generation, which would greatly reduce the concerns of developers.

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回答 (1 件)

Andy
Andy 2019 年 1 月 14 日
編集済み: Andy 2019 年 1 月 16 日
Hi Upol. Presently, referencing a component from an array of non-scalar values (accessing a field in a struct array) is not allowed in code generation.
As a workaround, for the time being you can rewrite the code to avoid the non-scalar access:
function uuindex = foo
OPS_FLT = struct('ACFT_ID', {"apple", "orange"});
uuindex=[];
for k = numel(OPS_FLT)
if OPS_FLT(k).ACFT_ID == OPS_FLT(2).ACFT_ID
uuindex = [uuindex, k];
end
end
end
*EDIT: I've modified code from version I original posted since it used another feature that also would not compile.
  3 件のコメント
Andy
Andy 2019 年 5 月 22 日
Hi Xie,
When running this through codegen "lines" ends up typed as a 1x:? struct array. As such you getting the error message about directly accessing a field of a nonscalar struct.
Could you try converting the line "A = lines.theta" into a for loop that copies each individual theta out to A? In other words change: A=lines.theta into:
A=zeros(1, size(lines,2));
for i=1:size(lines,2)
A(i)=lines(i).theta;
end
Also, I think you may have a problem with the following:
lines = struct('point1',[0,0],'point2',[0,0],'theta',0,'rho',0);
lines = repmat(line,1,0);
You pass "line" to repmat rather than "lines", "line" is a matlab function that returns an object.
This will end up causing a runtime error when you run the generated mex. You can resolve it either by commenting out this code or changing what you pass to repmat from "line" to "lines" (which is what I think you meant to do).
TripleSSSS
TripleSSSS 2020 年 6 月 10 日
I'd suggest using
A=coder.nullcopy(zeros(1, size(lines,2)));
instead of
A=zeros(1, size(lines,2));

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