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Implementing interparc function for dividing arc to segments

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Hari krishnan
Hari krishnan 2019 年 1 月 8 日
コメント済み: Hari krishnan 2019 年 1 月 8 日
I want to divide an arc to equal segments. I found a function called as https://in.mathworks.com/matlabcentral/fileexchange/34874-interparc, which can perform this. But i am slightly confused by the implementation. For eg: In the code below, i am trying to divide the arc in to 25 equal sections, What i want to know is whether each section have equal arc length. Any help to solve this will be appreciated.
px = X_coord_req; % X-values
py = Y_coord_req; % Y-values
pt = interparc(25,px,py,'pchip'); % do this this mean the arc is divided to 25 segments of equal arc length?
plot(px,py,'r',pt(:,1),pt(:,2),'b-o')
ax = gca;
ax.YDir = 'reverse';
axis([0 6600 0 5000])

  3 件のコメント

Hari krishnan
Hari krishnan 2019 年 1 月 8 日
Can anyone give an explanation to this?
Walter Roberson
Walter Roberson 2019 年 1 月 8 日
Yes each section will have equal arc length.
Hari krishnan
Hari krishnan 2019 年 1 月 8 日
@Walter Robinson . Thank you very much

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