question about fun defining
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I want to create this fun as below:
R=rand(100);
diff=rand(25);
sum_r1=rand(25);;
fun =@(x) x(:)+x(:).*diff(:)./sum_r1(:);
R_im=nlfilter(R,[2 2],fun);
In fact, I want to add the amount of (diff/sum_r1).x(:) in each neighborhood of 2 by 2 to x(:); I mean I have 1 diff and 1 sum_r1 for every 2 by 2 neighborhood of R. But it gives me an error!
Can anybody please help me?
4 件のコメント
Walter Roberson
2012 年 7 月 17 日
What error does it give?
Note: it is not a good idea to use a variable named "diff" as that will interfere with use of the MATLAB function named "diff"
Andrea
2012 年 7 月 17 日
Walter Roberson
2012 年 7 月 17 日
編集済み: Walter Roberson
2012 年 7 月 17 日
In your code, you do not have 1 diff and 1 sum_r1 for each 2 x 2 neighborhood in R: in your code, you have 1 diff and 1 sum_r1 total
Also, watch out: there are 2500 non-overlapping 2 x 2 neighborhoods in a 100 x 100 matrix, not merely 25. And nlfilter() does sliding windows, not non-overlapping windows.
Perhaps you should consider using blkproc() instead of nlfilter()
Andrea
2012 年 7 月 17 日
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