Hello,
I am trying to solve a 2nd order difference equation with given bounds. Specifically:
I need to solve for a sequence of ( for t = 1,2,...,50) such that:
$X_{t+2} = f( X_{t+1}, X_t) $, the exact function is inside the below loop.
Here is my code to solve this system, using shooting method. And it is very strange that I got a sequence of X are all equal for 0 for all t. And more strange, the number of iterations executed (which is denoted iter in the loop are 0).
I have been checking for hours, but could not find the mistake. If any one see what is wrong with my code, plz kindly let me know.
Thanks so much,
T = 5;
X = zeros(T+1,1)
X(1) = 10;
iter=0
while (abs(X(T+1)) > TOL);
X(2) = (LEFT + RIGHT)/2;
for i = 1:T-1;
X(i+2,1) = A * (1 + ALPHA * BETA)* (X(i+1,1))^ALPHA + (1-DELTA) * (1 + BETA) * X(i+1,1)...
- BETA * (A * (X(i,1))^ALPHA + (1 - DELTA) * X(i,1)) * (A * ALPHA * X(i+1,1)^(ALPHA - 1) + (1 - DELTA));
end;
if X(T+1,1)< 0
LEFT = X(2,1);
elseif X(T+1,1) > 0
RIGHT = X(2,1);
else break;
end;
iter=iter+1
end;

 採用された回答

Geoff Hayes
Geoff Hayes 2018 年 12 月 24 日

0 投票

heidi - try using the MATLAB debugger to step through your code to determine what is going on. Note the following code
T = 5;
X = zeros(T+1,1)
X(1) = 10;
iter=0
while (abs(X(T+1)) > TOL);
What is T supposed to represent? The maximum number of iterations or something else? Should you increment it on each iteration of the while loop? See how X is a 6x1 array of zeros except for the first element which is 10. Then, in the condition for the loop, you are accessing the sixth element (since T is five) of X which is zero...which is less than TOL and so you never enter the loop.
If X is supposed to represent all of the outputs on each iteration of the loop, then you probably want to initialize T to be one and then increment on each iteration and setting X(T) to be some value...but that will conflict with this code
for i = 1:T-1;
X(i+2,1) = A * (1 + ALPHA * BETA)* (X(i+1,1))^ALPHA + (1-DELTA) * (1 + BETA) * X(i+1,1)...
- BETA * (A * (X(i,1))^ALPHA + (1 - DELTA) * X(i,1)) * (A * ALPHA * X(i+1,1)^(ALPHA - 1) + (1 - DELTA));
end;
Perhaps this the shooting part of the algorithm (which I don't understand). Please use the debugger or add some comments to your code which describe what is being attempted.

1 件のコメント

heidi pham
heidi pham 2018 年 12 月 24 日
編集済み: heidi pham 2018 年 12 月 25 日
Thank you so so much.
I see what is wrong now: "which is less than TOL and so you never enter the loop."
that's why i got the result is 0 for all element of X.
I just meant to allocate memory by puting X a vector of zeros, then update it. But it causes the error as you pointed down.
I will revise my code and redo it to see if it goes well.
Thank you again!

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