How to count first identical elements without a for cycle?

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Mr M.
Mr M. 2018 年 11 月 21 日
編集済み: Rik 2018 年 11 月 21 日
I have a vector [3 3 3 3 3 4 1 1 0 0 0 5 6 3 3 1 1 1], and I want to count threes at the begining of the vector, so the result has to be 5.
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Rik
Rik 2018 年 11 月 21 日
You have now asked over 350 questions. Surely you have been linked to the tutorial multiple times. So you should know that you should show what you have tried so far to achieve this.
I also have a few points for clarification: Should the code measure the run length of the first run of 3s, or should it measure the length of the first run?

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Rik
Rik 2018 年 11 月 21 日
編集済み: Rik 2018 年 11 月 21 日
In case you want to measure the run length of the first run:
data=[3 3 3 3 3 4 1 1 0 0 0 5 6 3 3 1 1 1];
output=find(diff(data),1,'first');
And if you want to measure the run length of the first run of 3:
data=[5 3 3 3 3 3 4 1 1 0 0 0 5 6 3 3 1 1 1];
ind=find(data==3,1);
if ind>1
data(1:(ind-1))=[];
end
output=find(diff(data),1,'first');

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