Convert this C program into a Matlab program.

ex[1]=lx/J      %%first i term in ex matrix
ex[2]=mx/J      %%second j term in ex matrix
ex[3]=nx/J      %%third k term in ex matrix

for (i=0;i<9;i++)
for (j=0;i<27;j++)   
     N_matrix[i,j]=0;
end

for (i=0;i<9;i++)
     N_matrix(0,i)=N[i%3]*ex[i/3];
end

[Kevin Chng]

ex[1]=lx/J 
%%first i term in ex matrix ex[2]=mx/J 
%%second j term in ex matrix ex[3]=nx/J 
%%third k term in ex matrix

for (i=0;i<9;i++) 
for (j=0;i<27;j++) 
N_matrix[i,j]=0; 
end

for (i=0;i<9;i++) 
N_matrix(0,i)=N[i%3]*ex[i/3]; 
end

link for you to learn : https://www.mathworks.com/help/matlab/getting-started-with-matlab.html

I don't think anyone will answer this to you.

[Adam]

As C code goes that is about as trivial as it comes to convert to Matlab! It's just a few minor syntax changes (though vectorisation would be better than the straight for loop conversion).

[Jan]

@Virajan Verma: You are not a newbie in this forum. I've formatted the code for your today, but please mark the code with the mouse and press the "{} Code" button by your own in the future. Thanks.

This is not C code, because there is no "end" in C. What is N? Are you sure that you want to insert values in the first row, not column?

[Guillaume]

N_matrix(0,i) is also not correct C syntax. The brackets should be square.

And as Jan pointed out, it should probably be:

N_matrix[i,0]

Answer 1

[Jan]

ex = [lx; mx; nx] / J;
N  = rand(3, 1);  % ???
N_matrix = zeros(9, 27);
N_matrix(1, 1:9) = repmat(N, 3, 1) .* repelem(ex, 3, 1)

[Virajan Verma]

How do i convert this??

for i=1:9
    N_matrix(5,i+9)= N(rem(i,3))*ez(i/3);
    N_matrix(2,i)=N(rem(i,3))*ez(i/3);
end

[Virajan Verma]

N(1)=0.5*(epsilon3*epsilon3-epsilon3);        %%epsilon=natural coordinte
N(2)=(1-epsilon3*epsilon3);
N(3)=0.5*(epsilon3*epsilon3+epsilon3);

epsilon3 has 3 values: 1, 2, 3.

[Virajan Verma]

@Jan

[Walter Roberson]

That code creates a row vector for N, not a column vector. Try N(1,1), N(2,1), N(3,1) as the destinations