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Break a loop and get the step where the loop stopped

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Lu
Lu 2012 年 6 月 24 日
Dear everyone,
I have a function that calculates a test statistic and compares it to some critical values. If the test statistic is greater than the critical value, then the loop should break and it should give back the step k where the loop broke and it should calculate at "k-1" (one step before condition was met) maximum likelihood estimates. However, it is not working and it is not giving me back the step k where the loop breaks nor the quasi maximum likelihood estimates. I hope you could give me a hint on what am I doing wrong.
Thank you so much!
  2 件のコメント
Jan
Jan 2012 年 6 月 24 日
To understand the problem, the readers of your question have either to run your function or you have to explain, what the program does. Without knowing the inputs, we cannot run the program. You explain only, what the program doesn't do, but not, what it does.
Is the (b_T(k) > zk_values(k)) condition fulfilled for any k?!
Lu
Lu 2012 年 6 月 24 日
Dear Jan,
Thank you for the suggestion, I explained a bit more what the script is supposed to do :) I hope you can give me a hint on what am I doing wrong.
Thank you

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回答 (1 件)

Image Analyst
Image Analyst 2012 年 6 月 24 日
In the line:
theta_k_hat = WACD_11_Estimation(y(b_Intervals(k -1 +1 , 7) : b_Intervals(14, 8))) ;
what is the function "WACD_11_Estimation"? You don't seem to have used that before.
  3 件のコメント
Image Analyst
Image Analyst 2012 年 6 月 24 日
Do you know how to use the debugger? Set a breakpoint there. Is the value of k_hat correct? Then, if so, is the value theta_k_hat correct? Then if so, is the value hat_parameters correct? This is what you can learn if you know how to use the debugger. It's far more efficient than debugging via Answers postings and responses.
Lu
Lu 2012 年 6 月 24 日
Hi Image Analyst,
Thank you for your suggestion, I was checking the values of k_hat and theta_k_hat but they were correct, the problem was that the program was not estimating the maximum likelihood estimates and I didnt know why. Sometimes you miss a little detail that others might find and that is why I posted it on Answers.
In the end I got it to work.
Thank you for your help :)

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