How to change values of elements in a sparse matrix

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Ismaeel
Ismaeel 2018 年 8 月 9 日
編集済み: James Tursa 2018 年 8 月 9 日
I have the following sparse matrix:
(1,1) 1.1000
(2,2) 2.1000
(3,3) 0.1000
(4,4) 5.1000
(5,5) 0.6000
Created from a full matrix. I want to modify the sparse matrix by changing some values in the second column above. I do not want to change them in the original matrix. The reason is the full matrix is very large and the majority of elements are zeros. It takes a big portion of my computer memory (greater than 8 GB of my RAM capacity). The above matrix is only a small sample of my problem. Note that for this problem, the nonzero elements are located in the diagonal of the matrix.
Any idea?
Thanks
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Rik
Rik 2018 年 8 月 9 日
Variable in Matlab in general don't affect each other, so you can just change the elements. What errors are you encountering?

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James Tursa
James Tursa 2018 年 8 月 9 日
編集済み: James Tursa 2018 年 8 月 9 日
Not sure what your problem is. Sparse matrix elements can be changed directly just like full matrices. E.g.,
F = your full matrix
S = sparse(F); % your sparse matrix
S(3,2) = something; % change a value in S, does not affect F
F(5,2) = something else; % change a value in F, does not affect S
How many elements will you be changing?
  4 件のコメント
Ismaeel
Ismaeel 2018 年 8 月 9 日
I need to change all diagonal elements (82,000 elements).
James Tursa
James Tursa 2018 年 8 月 9 日
編集済み: James Tursa 2018 年 8 月 9 日
If there are already non-zero elements in the diagonal and you are changing them to other non-zero values, then a loop probably won't hurt you since in theory it would not require large amounts of memory to be copied. But if that is not the case, then doing it all at once will probably be a better method. E.g.,
v = a vector of 82000 values for the diagonal
S = your sparse matrix
S(1:82001:end) = v; % change all the diagonals at once using linear indexing

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