modify only the diagonal entries in a matrix?
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How can I Multiply the diagonal of a matrix by a number, for example; by 2?
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Jan
2018 年 7 月 9 日
編集済み: Jan
2018 年 7 月 9 日
A = rand(4,3);
s = size(A);
index = 1:s(1)+1:s(1)*s(2); % Indices of the main diagonal
A(index) = A(index) * 2
This touches the elements on the diagonal only.
6 件のコメント
Alvin Chen
2021 年 6 月 21 日
@Image Analyst For loop would work for sure, but would it be more performable without using loop? Just extract the logicals by the positions of the indices in A.
Image Analyst
2021 年 6 月 21 日
I don't know what you mean by "performable". Sure there are other ways to perform this operation that may work, however I did not understand your explanation of extracting the logicals so I invite you to show your non-for loop way that doubles the values in the 4 diagonals in a non-square matrix, for example a 5 by 10 matrix.
m = ones(5, 10)
Please show us.
その他の回答 (1 件)
Image Analyst
2019 年 2 月 26 日
Here's a way you can do it using eye() to create indexes of the diagonal. I show two ways,
- one to create another output matrix and leave the input matrix alone, and
- another to change the input matrix in place.
% Create a logical mask for the diagonal elements.
d = logical(eye(size(m)))
% First way: Create an output matrix m2, retaining the original m.
m2 = m % Initialize with a copy of m
% Multiply diagonal elements of m2 (in place) by 2.
m2(d) = m(d) * 2 % Input values are replaced.
% Second way: Change/replace the values in original matrix.
% Multiply diagonal elements (in place) by 2.
m(d) = m(d) * 2 % Input values are replaced.
The two ways are the same except if you want a second matrix for the output you have to copy the input matrix first.
2 件のコメント
Jan
2019 年 2 月 26 日
At least in current Matlab versions:
d = eye(size(m), 'logical'); % faster than: logical(...)
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