find the index of non-zero elements of three dimensional matrix and rank the them according to the value

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Chaoyang Jiang
Chaoyang Jiang 2018 年 6 月 11 日
コメント済み: Rik 2018 年 6 月 12 日
For a three dimentional matrix: A=randi(10,[10 10 5]), I want to find the index (x,y,z) of each non-zero element of A and then rank the all the non-zero elements according to the value.
However, when running the following code, it seems 'find' can only have three outputs. May I know how to achive this?
A=randi(10,[10 10 5]);
[x,y,z,val]=find(A);
sortrows([val,x,y,z],1)

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Rik
Rik 2018 年 6 月 11 日
You can use my FEX submission findND.
A=randi(10,[10 10 5]);
[x,y,z,val]=findND(A);
sortrows([val,x,y,z],1)
  2 件のコメント
Rik
Rik 2018 年 6 月 12 日
You're welcome, that's what I wrote that function for, glad to be of service

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