convert matrix to tensor

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SOUMYA SUVRA GHOSAL
SOUMYA SUVRA GHOSAL 2018 年 6 月 4 日
コメント済み: Aakash Deep 2018 年 6 月 5 日
i have a data set which has the following structure road_segment_id/<time_slot>/<driver_id>/<travel_time> Now I need to select randomly 100 driver ids and create a 3-d tensor with road_segment_id,driver_id,time-slot on 3 sides.Let the tensor be A then a(i,j,k)=c represents that time taken by driver j to traverse road segment i on time-slot k is c. the attached file showing a part of data set is there.
  1 件のコメント
SOUMYA SUVRA GHOSAL
SOUMYA SUVRA GHOSAL 2018 年 6 月 4 日
編集済み: SOUMYA SUVRA GHOSAL 2018 年 6 月 4 日
here's my code,please tell me where is the error
if
road=unique(M(:,1));
time_slot=unique(M(:,2));
user_id=unique(M(:,3));
n_road=numel(road);
n_time=numel(time_slot);
n_user=numel(user_id);
driver=intersect(user_id,randsample(user_id,100));
A=ones(n_road,100,n_time);
for ii=1:n_road
for jj=1:100
for kk=1:n_time
[r]=find(M(:,1)==road(ii) & M(:,3)==driver(jj) & M(:,2)==time(kk));
A(ii,jj,kk)=M(r,4);
end
end
end
A is the 3d array
its giving error that
"Assignment has more non-singleton rhs dimensions than non-singleton subscripts"
Error in tensor A(ii,jj,kk)=M(r,4);

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回答 (1 件)

Aakash Deep
Aakash Deep 2018 年 6 月 4 日
If this doesn't work you can still ask about it but try to mention more information about the dimensions of input matrix and output tensor.
  4 件のコメント
SOUMYA SUVRA GHOSAL
SOUMYA SUVRA GHOSAL 2018 年 6 月 4 日
Thank you so much Aakash, can you do me one last favour by telling how to modify the code. Means what should I write in the assignment statement.
Aakash Deep
Aakash Deep 2018 年 6 月 5 日
Hey Soumya, your approach is correct to populate the tensor. I am not exactly able to figure out why it is behaving like this but here are the few tips you should try:
  • After looking at the below statement,
[r]=find(M(:,1)==road(ii) & M(:,3)==driver(jj) & M(:,2)==time(kk));
I am assuming that the error is coming from M(:,3)==driver(jj) this part because the value of road can repeat as many time it wants and the value of time can also repeat but what can not repeat is the driver_id for the same pair of road and time (if it does then there is redundancy is your data).
  • There can be a possibility that the vector r contains same value multiple times. So just try to use unique on r and then use it as an index value.
  • There are highly chances that the vector r can be a null set because of the & operator so you should first check it if it is a single value or not before using it as a index value during assignment. This will fix some of your errors.
Hope this helps :)

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